A 0.450-kg hammer is moving horizontally at 7.00 m/s when it strikes a nail and comes to rest after driving the nail 1.00 cm into a board. (a) Calculate the duration of the impact. (b) What was the average force exerted on the nail?

Step-by-step solution In this problem a hammer strikes a nail and comes to rest calculate the duration of the impact and the average force exerted on the nail. Step 1 of 5 The change in momentum over a range of certain time is nothing but average force acting on it. Step 2 of 5 (a) Use following formula to find the time taken by the hamm er for distance is: Here d is the distance travelled, and is the velocity. Substitute for and for Since, the wall is not padded, so the nail will not come back. Therefore, the time span will be the time just required for inserting of nail that is . Step 3 of 5 (b) Use the following formula to find the change in velocity of hammer: Here, is the initial velocity and is the final velocity. The initial velocity is given as follows: After that, the hammer comes to the rest. So, the final velocity is, The change in velocity is given as follows: