A ball with an initial velocity of 10 m/s moves at an angle 60º above t?he + ?x -direction. The ball hits a vertical wall and bounces off so that it is moving 60º above? the ? ?x -direction with the same speed. What is the impulse delivered by the wall?
Step-by-step solution Step 1 of 5 Consider the following diagram of the motion of the ball as refer to book, Step 2 of 5 The impulse is implied only on the horizontal direction, because there is no effect of gravitational acceleration. Before hit the vertical wall it moves above the +x direction with the speed of 10 m/s. So, the horizontal initial speed is: Substitute for in above expression. Step 3 of 5 While returning from wall, everything is same, just the direction is changed. After h itting the vertical wall it moves above the –x direction with the speed m/s. the final horizontal speed will be: Substitute for in above expression,
Textbook: Physics: Principles with Applications
Author: Douglas C. Giancoli
Physics: Principles with Applications was written by and is associated to the ISBN: 9780130606204. Since the solution to 20PE from 8 chapter was answered, more than 365 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Physics: Principles with Applications, edition: 6. The full step-by-step solution to problem: 20PE from chapter: 8 was answered by , our top Physics solution expert on 03/03/17, 03:53PM. This full solution covers the following key subjects: Wall, ball, direction, initial, bounces. This expansive textbook survival guide covers 35 chapters, and 3914 solutions. The answer to “A ball with an initial velocity of 10 m/s moves at an angle 60º above t?he + ?x -direction. The ball hits a vertical wall and bounces off so that it is moving 60º above? the ? ?x -direction with the same speed. What is the impulse delivered by the wall?” is broken down into a number of easy to follow steps, and 51 words.