The accompanying summary data on CeO2 particle sizes (nm)

Chapter 1, Problem 12E

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QUESTION:

Problem 12E

The accompanying summary data on CeO2 particle sizes (nm) under certain experimental conditions was read from a graph in the article "Nanoceria—Energetics of Surfaces, Interfaces and Water Adsorption" (J. of the Amer. Ceramic Soc., 2011: 3992-3999):

a. What proportion of the observations are less than 5?

b. What proportion of the observations are at least 6?

c. Construct a histogram with relative frequency on the vertical axis and comment on interesting features. In particular, does the distribution of particle sizes appear to be reasonably symmetric or somewhat skewed? [Note: The investigators fit a lognormal distribution to the data; this is dis-cussed in Chapter 4.]

d. Construct a histogram with density on the vertical axis and compare to the histogram in (c).

Questions & Answers

QUESTION:

Problem 12E

The accompanying summary data on CeO2 particle sizes (nm) under certain experimental conditions was read from a graph in the article "Nanoceria—Energetics of Surfaces, Interfaces and Water Adsorption" (J. of the Amer. Ceramic Soc., 2011: 3992-3999):

a. What proportion of the observations are less than 5?

b. What proportion of the observations are at least 6?

c. Construct a histogram with relative frequency on the vertical axis and comment on interesting features. In particular, does the distribution of particle sizes appear to be reasonably symmetric or somewhat skewed? [Note: The investigators fit a lognormal distribution to the data; this is dis-cussed in Chapter 4.]

d. Construct a histogram with density on the vertical axis and compare to the histogram in (c).

ANSWER:

Answer

Step 1 of 5

From the given data find relative frequencies and densities

values

frequency

Relative frequencies

Frequency density

3.0-<3.5

5

5/131=0.038

5/5=1

3.5-<4.0

15

15/131=0.115

15/5=3

4.0-<4.5

27

27/131=0.206

27/5=5.4

4.5-<5.0

34

34/131=0.26

34/5=6.8

5.0-<5.5

22

22/131=0.168

22/5=4.4

5.5-<6.0

14

14/131=0.107

14/5=2.8

6.0-<6.5

7

7/131=0.053

7/5=1.4

6.5-<7.0

2

2/131=0.015

⅖=0.4

7.0-<7.5

4

4/131=0.031

⅘=0.8

7.5-<8.0

1

1/131=0.008

⅕=0.2

total

131

1

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