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Ionic Equations Decoded: From Total to Net in Aqueous Reactions
Chapter 4, Problem 80(choose chapter or problem)
Write balanced complete ionic and net ionic equations for each reaction.
a. \({K_2}S{O_4}\left( {aq} \right) + Ca{I_2}\left( {aq} \right) \to CaS{O_4}\left( s \right) + KI\left( {aq} \right)\)
b. \(N{H_4}Cl\left( {aq} \right) + NaOH\left( {aq} \right) \to {H_2}O\left( l \right) + N{H_3}\left( g \right) + NaCl\left( {aq} \right)\)
c. \(AgN{O_3}\left( {aq} \right) + NaCl\left( {aq} \right) \to AgCl\left( s \right) + NaN{O_3}\left( {aq} \right)\)
d. \(H{C_2}{H_3}{O_2}\left( {aq} \right) + {K_2}C{O_3}\left( {aq} \right) \to {H_2}O\left( l \right) + C{O_2}\left( g \right) + K{C_2}{H_3}{O_2}\left( {aq} \right)\)
Questions & Answers
QUESTION:
Write balanced complete ionic and net ionic equations for each reaction.
a. \({K_2}S{O_4}\left( {aq} \right) + Ca{I_2}\left( {aq} \right) \to CaS{O_4}\left( s \right) + KI\left( {aq} \right)\)
b. \(N{H_4}Cl\left( {aq} \right) + NaOH\left( {aq} \right) \to {H_2}O\left( l \right) + N{H_3}\left( g \right) + NaCl\left( {aq} \right)\)
c. \(AgN{O_3}\left( {aq} \right) + NaCl\left( {aq} \right) \to AgCl\left( s \right) + NaN{O_3}\left( {aq} \right)\)
d. \(H{C_2}{H_3}{O_2}\left( {aq} \right) + {K_2}C{O_3}\left( {aq} \right) \to {H_2}O\left( l \right) + C{O_2}\left( g \right) + K{C_2}{H_3}{O_2}\left( {aq} \right)\)
ANSWER:Step 1 of 4
a. The unbalanced molecular equation is shown below:
\({K_2}S{O_4}\left( {aq} \right) + Ca{I_2}\left( {aq} \right) \to CaS{O_4}\left( s \right) + KI\left( {aq} \right)\)
To balance the above equation, multiply KI by 2. The balanced molecular equation is as shown below:
\({K_2}S{O_4}\left( {aq} \right) + Ca{I_2}\left( {aq} \right) \to CaS{O_4}\left( s \right) + 2KI\left( {aq} \right)\)
Separate aqueous ionic compounds into constituent ions. The solid precipitate of calcium sulfate is not separated as it remains one unit. The complete ionic equation is shown below:
\(2{K^ + }\left( {aq} \right) + SO_4^{2 - }\left( {aq} \right) + C{a^{2 + }}\left( {aq} \right) + 2{I^ - }\left( {aq} \right) \to CaS{O_4}\left( s \right) + 2{K^ + }\left( {aq} \right) + 2{I^ - }\left( {aq} \right)\)
Eliminate the spectator ions. These ions do not change from one side of the reaction to another. The net ionic equation is as shown below:
\(SO_4^{2 - }\left( {aq} \right) + C{a^{2 + }}\left( {aq} \right) \to CaS{O_4}\left( s \right)\)