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Orthorhombic Unit Cell: Decoding Nickel Sulfate's Crystal Density
Chapter 20, Problem 20.8(a)(choose chapter or problem)
The orthorhombic unit cell of \(\rm{{NiSO}_4}\) has the dimensions a = 634 pm, b = 784 pm, and c = 516 pm, and the density of the solid is estimated as \(3.9\mathrm{\ g}\mathrm{\ cm}^{-3}\). Determine the number of formula units per unit cell and calculate a more precise value of the density.
Questions & Answers
QUESTION:
The orthorhombic unit cell of \(\rm{{NiSO}_4}\) has the dimensions a = 634 pm, b = 784 pm, and c = 516 pm, and the density of the solid is estimated as \(3.9\mathrm{\ g}\mathrm{\ cm}^{-3}\). Determine the number of formula units per unit cell and calculate a more precise value of the density.
ANSWER:Step 1 of 3
Orthorhombic unit cell
The orthorhombic unit cell illustrates one of the 7 crystal lattices containing a rectangular prism with a rectangular base and height. Due to this, the lengths along each axis differ, and the angle between each axis is 90 degrees.
The density of an orthorhombic unit cell is:
\(d = \dfrac{{Nm}}{V}\)
Where N represents the number of formula units in one unit cell, m is the mass of one formula unit, and V is unit cell volume.
The product of the number of formula units and the mass of one formula unit gives the total mass of one unit cell.
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Orthorhombic Unit Cell: Decoding Nickel Sulfate's Crystal Density
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The video offers an insightful look into the orthorhombic unit cell, a unique crystal lattice structure. By exploring nickel sulfate's unit cell and its specific dimensions, we determine both the number of formula units and the density of this crystalline structure.