Solution Found!
A 75-kg meteorite buries itself 5.0 m into soft mud.
Chapter 7, Problem 7.72(choose chapter or problem)
A 75-kg meteorite buries itself 5.0 m into soft mud. The force between the meteorite and the mud is given by \(F(x)=\left(640 \mathrm{~N} / \mathrm{m}^{3}\right) x^{3}\), where x is the depth in the mud. What was the speed of the meteorite when it initially impacted the mud?
Questions & Answers
QUESTION:
A 75-kg meteorite buries itself 5.0 m into soft mud. The force between the meteorite and the mud is given by \(F(x)=\left(640 \mathrm{~N} / \mathrm{m}^{3}\right) x^{3}\), where x is the depth in the mud. What was the speed of the meteorite when it initially impacted the mud?
ANSWER:Step 1 of 7
The given values are
\(\begin{array}{l}
m=75 \mathrm{~kg}\\
\begin{array}{l}
F(x)=\left(640 \mathrm{~N} / \mathrm{m}^{3}\right) x^{3} \\
x=5.0 \mathrm{~m}
\end{array}
\end{array}\)
Our goal is to calculate the initial speed of the meteorite.