The cotter is used to hold the two rods together.

Chapter 1, Problem 1-80

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QUESTION:

The cotter is used to hold the two rods together. Determine the smallest thickness t of the cotter and the smallest diameter d of the rods. All parts are made of steel for which the failure normal stress is \(\sigma_{\text {fail }}=500 \mathrm{MPa}\) and the failure shear stress is \(\tau_{\text {fail }}=375 \mathrm{MPa}\). Use a factor of safety of \(\left.(\text { F.S. })_{t}=2.50 \text { in tension and (F.S. }\right)_{s}=1.75 \text { in shear. }\)

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QUESTION:

The cotter is used to hold the two rods together. Determine the smallest thickness t of the cotter and the smallest diameter d of the rods. All parts are made of steel for which the failure normal stress is \(\sigma_{\text {fail }}=500 \mathrm{MPa}\) and the failure shear stress is \(\tau_{\text {fail }}=375 \mathrm{MPa}\). Use a factor of safety of \(\left.(\text { F.S. })_{t}=2.50 \text { in tension and (F.S. }\right)_{s}=1.75 \text { in shear. }\)

ANSWER:

Problem 1-80

The cotter is used to hold the two rods together. Determine the smallest thickness t of the cotter and the smallest diameter d of the rods. All parts are made of steel for which the failure normal stress is sfail = 500 MPa and the failure shear stress is . Use a factor of safety of  in tension and  in shear.

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The cotter is used to hold the two rods together.Determine the smallest thickness  of the cotter and the smallest diameter  of the rods.all parts are made of steel for which the failure normal stress is  and the failure shear stress is .use a factor of safety of  in tension and  in shear.

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