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# A 1.80-kg connecting rod from a car engine is pivoted ISBN: 9780321675460 31

## Solution for problem 53E Chapter 14

University Physics | 13th Edition

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Problem 53E

A 1.80-kg connecting rod from a car engine is pivoted about a horizontal knife edge as shown in ?Fig. E14.55?. The center of gravity of the rod was located by balancing and is 0.200 m from the pivot. When the rod is set into small-amplitude oscillation, it makes 100 complete swings in 120 s. Calculate the moment of inertia of the rod about the rotation axis through the pivot.

Step-by-Step Solution:

Solution 53E Step 1: Mass of the rod m = 1.80 kg Distance from the center of gravity d = 0.20 m Time period for 100 swings = 120 s Time period for one swing T = 1.2 s

Step 2 of 3

Step 3 of 3

##### ISBN: 9780321675460

Since the solution to 53E from 14 chapter was answered, more than 584 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: University Physics, edition: 13. University Physics was written by and is associated to the ISBN: 9780321675460. This full solution covers the following key subjects: rod, pivot, inertia, calculate, Car. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. The answer to “A 1.80-kg connecting rod from a car engine is pivoted about a horizontal knife edge as shown in ?Fig. E14.55?. The center of gravity of the rod was located by balancing and is 0.200 m from the pivot. When the rod is set into small-amplitude oscillation, it makes 100 complete swings in 120 s. Calculate the moment of inertia of the rod about the rotation axis through the pivot.” is broken down into a number of easy to follow steps, and 69 words. The full step-by-step solution to problem: 53E from chapter: 14 was answered by , our top Physics solution expert on 05/06/17, 06:07PM.

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A 1.80-kg connecting rod from a car engine is pivoted