A 1.80-kg connecting rod from a car engine is pivoted about a horizontal knife edge as shown in ?Fig. E14.55?. The center of gravity of the rod was located by balancing and is 0.200 m from the pivot. When the rod is set into small-amplitude oscillation, it makes 100 complete swings in 120 s. Calculate the moment of inertia of the rod about the rotation axis through the pivot.

Solution 53E Step 1: Mass of the rod m = 1.80 kg Distance from the center of gravity d = 0.20 m Time period for 100 swings = 120 s Time period for one swing T = 1.2 s