How many total moles of ions are released when each of the following samples dissolves completely in water?
(a) 0.734 mol of \(\mathrm{Na}_{2} \mathrm{HPO}_{4}\)
(b) 3.86 g of \(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}\)
(c) \(8.66 \times 10^{20}\) formula units of \(\mathrm{NiCl}_{2}\)
Step 1 of 3
Here we have to calculate how many total moles of ions are released when each of the following samples dissolves completely in water.
(a)
1st we will write a chemical equation for the dissociation of .
From the above reaction it has been found that 3 moles of ions are released when one mole of dissolves, so the total number of moles released can be calculated as,
0.734 mol
3 mol ions / mol
= 1.47 mol of ions
ions
0.734 moles of is also present.
Thus total mole of ion = 1.47 + 0.734 = 2.202 mol
Thus 2.202 moles of ions are released when samples dissolves completely in water.
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