How many total moles of ions are released when each of the following samples dissolves completely in water?

(a) 0.734 mol of \(\mathrm{Na}_{2} \mathrm{HPO}_{4}\)

(b) 3.86 g of \(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}\)

(c) \(8.66 \times 10^{20}\) formula units of \(\mathrm{NiCl}_{2}\)

Step 1 of 3

Here we have to calculate how many total moles of ions are released when each of the following samples dissolves completely in water.

(a)

1st we will write a chemical equation for the dissociation of .

From the above reaction it has been found that 3 moles of ions are released when one mole of dissolves, so the total number of moles released can be calculated as,

0.734 mol 3 mol ions / mol = 1.47 mol of ions ions

0.734 moles of is also present.

Thus total mole of ion = 1.47 + 0.734 = 2.202 mol

Thus 2.202 moles of ions are released when samples dissolves completely in water.

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