### Solution Found! # Using 50g I?O? in Respirators: CO Removal Capacity & Remaining I? Mass

Chapter 6, Problem 6.23

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QUESTION:

Diiodine pentoxide is used in respirators to remove carbon monoxide from air:

$$\mathrm{I}_{2} \mathrm{O}_{5}(s)+5 \mathrm{CO}(\mathrm{g}) \longrightarrow \mathrm{I}_{2}(s)+5 \mathrm{CO}_{2}(\mathrm{~g})$$

(a) What mass of carbon monoxide could be removed from air by a respirator that contains 50.0 g of diiodine pentoxide?

(b) What mass of $$\mathrm{I}_{2}$$ would remain in the respirator?

QUESTION:

Diiodine pentoxide is used in respirators to remove carbon monoxide from air:

$$\mathrm{I}_{2} \mathrm{O}_{5}(s)+5 \mathrm{CO}(\mathrm{g}) \longrightarrow \mathrm{I}_{2}(s)+5 \mathrm{CO}_{2}(\mathrm{~g})$$

(a) What mass of carbon monoxide could be removed from air by a respirator that contains 50.0 g of diiodine pentoxide?

(b) What mass of $$\mathrm{I}_{2}$$ would remain in the respirator?

Step 1 of 3

(a) The given reaction is as follows;

$$\mathrm{I}_{2} \mathrm{O}_{5}(s)+5 \mathrm{CO}(g) \rightarrow \mathrm{I}_{2}(s)+5 \mathrm{CO}_{2}(g)$$

$$\begin{array}{l}\text{Molar mass of } \mathrm{I}_{2} \mathrm{O}_{5}=333.81 \mathrm{~g} / \mathrm{mol}\\ \text{Given mass } =50.0 \mathrm{~g}\end{array}$$

Let’s calculate the number of moles of diiodine:

$$\text { Number of moles of } \mathrm{I}_{2} \mathrm{O}_{5}=\frac{\text { Given mass }}{\text { Molar mass }}$$

From the reaction, $$1 \mathrm{~mol} \text { of } \mathrm{I}_{2} \mathrm{O}_{5} \text { reacts with } \rightarrow 5 \mathrm{~mol} \mathrm{CO}$$

The conversion factor will be:

$$\frac{5 \mathrm{~mol} \mathrm{CO}}{1 \mathrm{~mol}_{2} \mathrm{O}_{5}}$$