An air-standard Otto cycle has a compression ratio of 6

Chapter 9, Problem 9.7

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QUESTION:

An air-standard Otto cycle has a compression ratio of 6 and the temperature and pressure at the beginning of the compression process are \(520^{\circ} \mathrm{R}\) and \(14.2 \mathrm{lbf} / \mathrm{in}^{2}{ }^{2}\), respectively. The heat addition per unit mass of air is 600 Btu/lb. Determine

(a) the maximum temperature, in \( {\circ} \mathrm{F}\).

(b) the maximum pressure, in \(\text { in lbf/in. }{ }^{2}\).

(c) the thermal efficiency.

(d) the mean effective pressure, in \(\text { in lbf/in. }{ }^{2}\)

Questions & Answers

QUESTION:

An air-standard Otto cycle has a compression ratio of 6 and the temperature and pressure at the beginning of the compression process are \(520^{\circ} \mathrm{R}\) and \(14.2 \mathrm{lbf} / \mathrm{in}^{2}{ }^{2}\), respectively. The heat addition per unit mass of air is 600 Btu/lb. Determine

(a) the maximum temperature, in \( {\circ} \mathrm{F}\).

(b) the maximum pressure, in \(\text { in lbf/in. }{ }^{2}\).

(c) the thermal efficiency.

(d) the mean effective pressure, in \(\text { in lbf/in. }{ }^{2}\)

ANSWER:

Step 1 of 4

a) To solve this problem we will use the given temperatures  and pressure  to calculate the maximum temperature of the cycle . We will start with the calculation of the parameter . For the calculation we will need the given compression ratio  and parameter  determined from the ideal gas table.

From the ideal gas tables we can then interpolate the temperature  and internal energy  using the parameter

We can then use the given heat  to calculate the internal energy . Work  is equal to zero.

From the internal energy  we can then evaluate temperature  for the ideal gas tables.

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