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Get Full Access to University Physics - 13 Edition - Chapter 19 - Problem 38p
Get Full Access to University Physics - 13 Edition - Chapter 19 - Problem 38p

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# Figure shows the pV-diagram for an isothermal expansion of

ISBN: 9780321675460 31

## Solution for problem 38P Chapter 19

University Physics | 13th Edition

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University Physics | 13th Edition

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Problem 38P

Figure shows the ?pV?-diagram for an isothermal expansion of 1.50 mol of an ideal gas, at a temperature of 15.0°C. (a) What is the change in internal energy of the gas? Explain. (b) Calculate the work done by (or on) the gas and the heat absorbed (or released) by the gas during the expansion. Figure:

Step-by-Step Solution:

Solution 38P Step 1: (a).Internal energy is due to motion of particles in a system. As internal energy depends on temperature. As we know temperature in isothermal process is constant so the internal energy will also be constant thus the change in internal energy will be zero. U = 0

Step 2 of 3

Step 3 of 3

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