Solution Found!
Figure shows the pV-diagram for an isothermal expansion of
Chapter 19, Problem 38P(choose chapter or problem)
CALC Figure P19.38 shows the pV-diagram for an isothermal expansion of 1.50 mol of an ideal gas, at a temperature of 15.0°C.
(a) What is the change in internal energy of the gas? Explain.
(b) Calculate the work done by (or on) the gas and the heat absorbed (or released) by the gas during the expansion.
Questions & Answers
QUESTION:
CALC Figure P19.38 shows the pV-diagram for an isothermal expansion of 1.50 mol of an ideal gas, at a temperature of 15.0°C.
(a) What is the change in internal energy of the gas? Explain.
(b) Calculate the work done by (or on) the gas and the heat absorbed (or released) by the gas during the expansion.
ANSWER:
Solution 38P Step 1: (a).Internal energy is due to motion of particles in a system. As internal energy depends on temperature. As we know temperature in isothermal process is constant so the internal energy will also be constant thus the change in internal energy will be zero. U = 0