Explain why or why not Determine whether the following statements are true and give an explanation or counterexample. Assume f and f_ are continuous functions for all real numbers. a. If A1x2 = 1 x a f 1t2 dt and f 1t2 = 2t - 3, then A is a quadratic function. b. Given an area function A1x2 = 1 x a f 1t2 dt and an antiderivative F of f , it follows that A_1x2 = F 1x2. c. 1 b a f _1x2 dx = f 1b2 - f 1a2. d. If f is continuous on 3a, b4 and 1 b a _ f 1x2 _ dx = 0, then f 1x2 = 0 on 3a, b4. e. If the average value of f on 3a, b4 is zero, then f 1x2 = 0 on 3a, b4. f. 1 b a 12f 1x2 - 3g1x22 dx = 21 b a f 1x2 dx + 31 a b g1x2 dx. g. 1f _1g1x22g_1x2 dx = f 1g1x22 + C.
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Textbook Solutions for Calculus: Early Transcendentals
Question
Displacement from velocity A particle moves along a line with a velocity given by v1t2 = 5 sin pt starting with an initial position s102 = 0. Find the displacement of the particle between t = 0 and t = 2, which is given by s1t2 = 1 2 0 v1t2 dt. Find the distance traveled by the particle during this interval, which is 1 2 0 _ v1t2 _ dt.
Solution
The first step in solving 5 problem number 45 trying to solve the problem we have to refer to the textbook question: Displacement from velocity A particle moves along a line with a velocity given by v1t2 = 5 sin pt starting with an initial position s102 = 0. Find the displacement of the particle between t = 0 and t = 2, which is given by s1t2 = 1 2 0 v1t2 dt. Find the distance traveled by the particle during this interval, which is 1 2 0 _ v1t2 _ dt.
From the textbook chapter Integration you will find a few key concepts needed to solve this.
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