Give an example of a nonincreasing sequence with a limit.
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Textbook Solutions for Calculus: Early Transcendentals
Question
Arithmetic-geometric mean Pick two positive numbers a0 and b0 with a0 7 b0, and write out the first few terms of the two sequences 5an6 and 5bn6: an + 1 = an + bn 2 , bn + 1 = 1an bn , for n = 0, 1, 2c. (Recall that the arithmetic mean A = 1p + q2>2 and the geometric mean G = 1pq of two positive numbers p and q satisfy A G.) a. Show that an 7 bn for all n. b. Show that 5an6 is a decreasing sequence and 5bn6 is an increasing sequence. c. Conclude that 5an6 and 5bn6 converge. d. Show that an + 1 - bn + 1 6 1an - bn2>2 and conclude that lim nS_ an = lim nS_ bn. The common value of these limits is called the arithmetic-geometric mean of a0 and b0, denoted AGM1a0, b02. e. Estimate AGM112, 202. Estimate Gauss constant 1>AGM11, 122.
Solution
The first step in solving 8.2 problem number 102 trying to solve the problem we have to refer to the textbook question: Arithmetic-geometric mean Pick two positive numbers a0 and b0 with a0 7 b0, and write out the first few terms of the two sequences 5an6 and 5bn6: an + 1 = an + bn 2 , bn + 1 = 1an bn , for n = 0, 1, 2c. (Recall that the arithmetic mean A = 1p + q2>2 and the geometric mean G = 1pq of two positive numbers p and q satisfy A G.) a. Show that an 7 bn for all n. b. Show that 5an6 is a decreasing sequence and 5bn6 is an increasing sequence. c. Conclude that 5an6 and 5bn6 converge. d. Show that an + 1 - bn + 1 6 1an - bn2>2 and conclude that lim nS_ an = lim nS_ bn. The common value of these limits is called the arithmetic-geometric mean of a0 and b0, denoted AGM1a0, b02. e. Estimate AGM112, 202. Estimate Gauss constant 1>AGM11, 122.
From the textbook chapter Sequences you will find a few key concepts needed to solve this.
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