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When two point charges of equal mass and charge are
Chapter 21, Problem 14DQ(choose chapter or problem)
When two point charges of equal mass and charge are released on a frictionless table, each has an initial acceleration (magnitude) a0. If instead you keep one fixed and release the other one, what will be its initial acceleration: a0, 2a0, or a0/2? Explain.
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QUESTION:
When two point charges of equal mass and charge are released on a frictionless table, each has an initial acceleration (magnitude) a0. If instead you keep one fixed and release the other one, what will be its initial acceleration: a0, 2a0, or a0/2? Explain.
ANSWER:Solution 14DQ Step 1 of 2: The magnitude of forces F | | = F | so the acceleration will be the same because force does not change. | 1| | 2| According to Newtons secon law F F = ma so a = m