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(a) What must the charge (sign and magnitude) of a 1.45-g
Chapter 21, Problem 29E(choose chapter or problem)
(a) What must the charge (sign and magnitude) of a 1.45-g particle be for it to remain stationary when placed in a downward-directed electric field of magnitude 650 N/C? (b) What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight?
Questions & Answers
QUESTION:
(a) What must the charge (sign and magnitude) of a 1.45-g particle be for it to remain stationary when placed in a downward-directed electric field of magnitude 650 N/C? (b) What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight?
ANSWER:Solution 29E Step 1 of 5: Weight is the force exerted by an object like earth on the other objects having mass. It is due to the weight of the object, as given below, when an object of mass m placed on table, Weight, W= mg Where m is the mass of the object and g is the acceleration due to gravity Electric field strength is the force exerted by the charge at point per unit charge. That is force per unit charge. E = Force/charge = F/q Therefore Electrostatic force, F = E q Where E is the electric field strength, F is the force and q is the charge.