Solved: PROBLEM 18EAt t = 0 a sealed test tube containing

Suppose it is known that the population of the community in Problem 1 is 10,000 after 3 years. What was the initial population \(P_{0}\)? What will be the population in 10 years? How fast is the population growing at t = 10? Text Transcription: P_0

The population of a community is known to increase at a rate proportional to the number of people present at time t. If an initial population \(P_{0}\) has doubled in 5 years, how long will it take to triple? To quadruple? Text Transcription: P_0

The population of a town grows at a rate proportional to the population present at time t. The initial population of 500 increases by 15% in 10 years. What will be the population in 30 years? How fast is the population growing at t = 30?

The population of bacteria in a culture grows at a rate proportional to the number of bacteria present at time t. After 3 hours it is observed that 400 bacteria are present. After 10 hours 2000 bacteria are present. What was the initial number of bacteria?

The radioactive isotope of lead, Pb-209, decays at a rate proportional to the amount present at time t and has a halflife of 3.3 hours. If 1 gram of this isotope is present initially, how long will it take for 90% of the lead to decay?

What Goes U p . . . (a) It is well known that the model in which air resistance is ignored, part (a) of Problem 36, predicts that the time \(t_{a}\) it takes the cannonball to attain its maximum height is the same as the time \(t_{d}\) it takes the cannonball to fall from the maximum height to the ground. Moreover, the magnitude of the impact velocity \(v_{i}\) will be the same as the initial velocity \(v_{0}\) of the cannonball. Verify both of these results. (b) Then, using the model in Problem 37 that takes air resistance into account, compare the value of \(t_{a}\) with \(t_{d}\) and the value of the magnitude of \(v_{i}\) with \(v_{0}\). A root-finding application of a CAS (or graphic calculator) may be useful here. Text Transcription: t_a t_d v_i v_0

Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of decay is proportional to the amount of the substance present at time t, find the amount remaining after 24 hours.

Determine the half-life of the radioactive substance described in Problem 6.

Archaeologists used pieces of burned wood, or charcoal, found at the site to date prehistoric paintings and drawings on walls and ceilings of a cave in Lascaux, France. See Figure 3.1.10. Use the information on page 86 to determine the approximate age of a piece of burned wood, if it was found that 85.5% of the C-14 found in living trees of the same type had decayed.

(a) Consider the initial-value problem dA/dt = kA, \(A(0)=A_{0}\) as the model for the decay of a radioactive substance. Show that, in general, the half-life T of the substance is T = (ln 2)k. (b) Show that the solution of the initial-value problem in part (a) can be written \(A(t)=A_{0} 2^{-t / T}\). (c) If a radioactive substance has the half-life T given in part (a), how long will it take an initial amount \(A_{0}\) of the substance to decay to \(\frac{1}{8} A_{0}\) ? Text Transcription: A(0)=A_0 A(t) = A_0 2^-t/T A_0 1/8 A_0

When a vertical beam of light passes through a transparent medium, the rate at which its intensity I decreases is proportional to I(t), where t represents the thickness of the medium (in feet). In clear seawater, the intensity 3 feet below the surface is 25% of the initial intensity \(I_{0}\) of the incident beam. What is the intensity of the beam 15 feet below the surface? Text Transcription: I_0

When interest is compounded continuously, the amount of money increases at a rate proportional to the amount S present at time t, that is, dS/dt = rS, where r is the annual rate of interest. (a) Find the amount of money accrued at the end of 5 years when $5000 is deposited in a savings account drawing \(5 \frac{3}{4} \%\) annual interest compounded continuously. (b) In how many years will the initial sum deposited have doubled? (c) Use a calculator to compare the amount obtained in part (a) with the amount \(S=5000\left(1+\frac{1}{4}(0.0575)\right)^{5(4)}\) that is accrued when interest is compounded quarterly. Text Transcription: 5 3/4 % S = 5000 (1+1/4(0.0575))^5(4)

The Shroud of Turin, which shows the negative image of the body of a man who appears to have been crucified, is believed by many to be the burial shroud of Jesus of Nazareth. See Figure 3.1.11. In 1988 the Vatican granted permission to have the shroud carbon-dated. Three independent scientific laboratories analyzed the cloth and concluded that the shroud was approximately 660 years old,* an age consistent with its historical appearance. Using this age, determine what percentage of the original amount of C-14 remained in the cloth as of 1988.

A thermometer is removed from a room where the temperature is \(70^{\circ}\) F and is taken outside, where the air temperature is \(10^{\circ}\) F. After one-half minute the thermometer reads \(50^{\circ}\) F. What is the reading of the thermometer at t = 1 min? How long will it take for the thermometer to reach \(15^{\circ}\) F? Text Transcription: 70^circ 10^circ 50^circ 15^circ

A thermometer is taken from an inside room to the outside, where the air temperature is \(5^{\circ}\) F. After 1 minute the thermometer reads \(55^{\circ}\) F, and after 5 minutes it reads \(30^{\circ}\) F. What is the initial temperature of the inside room? Text Transcription: 5^circ 55^circ 30^circ

A small metal bar, whose initial temperature was \(20^{\circ}\) C, is dropped into a large container of boiling water. How long will it take the bar to reach \(90^{\circ}\) C if it is known that its temperature increases \(2^{\circ}\) in 1 second? How long will it take the bar to reach \(98^{\circ}\) C? Text Transcription: 20^circ 90^circ 2^circ 98^circ

A thermometer reading \(70^{\circ}\) F is placed in an oven preheated to a constant temperature. Through a glass window in the oven door, an observer records that the thermometer reads \(110^{\circ}\) F after a minute and \(145^{\circ}\) F after \(\frac{1}{2}\) minute. How hot is the oven? Text Transcription: 70^circ 110^circ 145^circ 1/2

At t = 0 a sealed test tube containing a chemical is immersed in a liquid bath. The initial temperature of the chemical in the test tube is \(80^{\circ}\) F. The liquid bath has a controlled temperature (measured in degrees Fahrenheit) given by \(T_{m}(t)=100-40 e^{-0.1 t}\), \(t \geq 0\), where t is measured in minutes. (a) Assume that k = -0.1 in (2). Before solving the IVP, describe in words what you expect the temperature T(t) of the chemical to be like in the short term. In the long term. (b) Solve the initial-value problem. Use a graphing utility to plot the graph of T(t) on time intervals of various lengths. Do the graphs agree with your predictions in part (a)? Text Transcription: 80^circ T_m (t) = 100 - 40e^-0.1t t geq 0

Two large containers A and B of the same size are filled with different fluids. The fluids in containers A and B are maintained at \(0^{\circ}\) C and \(100^{\circ}\) C, respectively. A small metal bar, whose initial temperature is \(100^{\circ}\) C, is lowered into container A. After 1 minute the temperature of the bar is \(90^{\circ}\) C. After 2 minutes the bar is removed and instantly transferred to the other container. After 1 minute in container B the temperature of the bar rises \(10^{\circ}\). How long, measured from the start of the entire process, will it take the bar to reach \(99.9^{\circ}\) C? Text Transcription: 0^circ 100^circ 90^circ 10^circ 99.9^circ

A dead body was found within a closed room of a house where the temperature was a constant \(70^{\circ}\) F. At the time of discovery the core temperature of the body was determined to be \(85^{\circ}\) F. One hour later a second measurement showed that the core temperature of the body was \(80^{\circ}\) F. Assume that the time of death corresponds to t = 0 and that the core temperature at that time was \(98.6^{\circ}\) F. Determine how many hours elapsed before the body was found. [Hint: Let \(t_{1}>0\) denote the time that the body was discovered.] Text Transcription: 70^circ 85^circ 80^circ 98.6^circ t_1 > 0

The rate at which a body cools also depends on its exposed surface area S. If S is a constant, then a modification of (2) is \(\frac{d T}{d t}=k S\left(T-T_{m}\right)\) where k < 0 and \(T_{m}\) is a constant. Suppose that two cups A and B are filled with coffee at the same time. Initially, the temperature of the coffee is \(150^{\circ}\) F. The exposed surface area of the coffee in cup B is twice the surface area of the coffee in cup A. After 30 min the temperature of the coffee in cup A is \(100^{\circ}\) F. If \(T_{m}=70^{\circ}\) F, then what is the temperature of the coffee in cup B after 30 min? Text Transcription: dT/dt = kS(T-T_m) T_m 150^circ 100^circ T_m = 70^circ

Solve Problem 21 assuming that pure water is pumped into the tank.

A tank contains 200 liters of fluid in which 30 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pumped into the tank at a rate of 4 L/min; the well-mixed solution is pumped out at the same rate. Find the number A(t) of grams of salt in the tank at time t.

A large tank is filled to capacity with 500 gallons of pure water. Brine containing 2 pounds of salt per gallon is pumped into the tank at a rate of 5 gal/min. The well mixed solution is pumped out at the same rate. Find the number A(t) of pounds of salt in the tank at time t.

In Problem 23, what is the concentration c(t) of the salt in the tank at time t? At t = 5 min? What is the concentration of the salt in the tank after a long time, that is, as \(t \longrightarrow \infty\) ? At what time is the concentration of the salt in the tank equal to one-half this limiting value? Text Transcription: t longarrow infty

Solve Problem 23 under the assumption that the solution is pumped out at a faster rate of 10 gal/min. When is the tank empty?

A large tank is partially filled with 100 gallons of flui in which 10 pounds of salt is dissolved. Brine containing ½ pound of salt per gallon is pumped into the tank at a rate of 6 gal/min. The well-mixed solution is then pumped out at a slower rate of 4 gal/min. Find the number of pounds of salt in the tank after 30 minutes.

Determine the amount of salt in the tank at time t in Example 5 if the concentration of salt in the inflow is variable and given by \(c_{i n}(t)=2+\sin (t / 4)\)lb/gal. Without actually graphing, conjecture what the solution curve of the IVP should look like. Then use a graphing utility to plot the graph of the solution on the interval [0, 300]. Repeat for the interval [0, 600] and compare your graph with that in Figure 3.1.5(a). Text Transcription: cin(t) 2 sin(t4)

In Example 5 the size of the tank containing the salt mixture was not given. Suppose, as in the discussion following Example 5, that the rate at which brine is pumped into the tank is 3 gal/min but that the well stirred solution is pumped out at a rate of 2 gal/min. It stands to reason that since brine is accumulating in the tank at the rate of 1 gal/min, any finite tank must eventually overflo . Now suppose that the tank has an open top and has a total capacity of 400 gallons. (a) When will the tank overflow (b) What will be the number of pounds of salt in the tank at the instant it overflows (c) Assume that although the tank is overflowing, brine solution continues to be pumped in at a rate of 3 gal/min and the well-stirred solution continues to be pumped out at a rate of 2 gal/min. Devise a method for determining the number of pounds of salt in the tank at t = 150 minutes. (d) Determine the number of pounds of salt in the tank as \(t \rightarrow \infty\). Does your answer agree with your intuition? (e) Use a graphing utility to plot the graph of A(t) on the interval [0, 500). Text Transcription: t rightarrow infty

A 30-volt electromotive force is applied to an LR-series circuit in which the inductance is 0.1 henry and the resistance is 50 ohms. Find the current i(t) if i(0) = 0. Determine the current as \(t \longrightarrow \infty\) . Text Transcription: t longarrow infty

Solve equation (7) under the assumption that \(E(t)=E_{0} \sin \omega t \text { and } i(0)=i_{0}\). Text Transcription: E(t)=E_0 sin omegat i(0)=i_0

A 100-volt electromotive force is applied to an RC-series circuit in which the resistance is 200 ohms and the capacitance is \(10^{-4}\) farad. Find the charge q(t) on the capacitor if q(0) = 0. Find the current i(t). Text Transcription: 10^-4

A 200-volt electromotive force is applied to an RC-series circuit in which the resistance is 1000 ohms and the capacitance is \(5 \times 10^{-6}\) farad. Find the charge q(t) on the capacitor if i(0) = 0.4. Determine the charge and current at t = 0.005 s. Determine the charge as \(t \longrightarrow \infty\). Text Transcription: 5 x 10^-6 t longrightarrow infty

An electromotive force \(E(t)=\left\{\begin{array}{lllr} 120, & 0 & t \ \ \ \ 20 \\ 0, & & t>20 \end{array}\right.\) is applied to an LR-series circuit in which the inductance is 20 henries and the resistance is 2 ohms. Find the current i(t) if i(0) = 0. Text Transcription: E(t) = left begin array lllr 120, & 0 & t & 20 \\ 0, & & t>20 end array right.

Suppose an RC-series circuit has a variable resistor. If the resistance at time t is given by \(R=k_{1}+k_{2} t\), where \(k_{1}\) and \(k_{2}\) are known positive constants, then (9) becomes \(\left(k_{1}+k_{2} t\right) \frac{d q}{d t}+\frac{1}{C} q=E(t) .\) If \E(t)=E_{0} \text { and } q(0)=q_{0}\), where \(E_{0} \text { and } q_{0}\) constants, show that \(q(t)=E_{0} C+\left(q_{0}-E_{0} C\right)\left(\frac{k_{1}}{k_{1}+k_{2} t}\right)^{1 / C k_{2}}\) Text Transcription: R=k_1+k_2 t, k_1 k_2 left k_1+k_2 right frac d q d t + frac 1 C q=E(t) E(t)=E_0 q(0)=q_0 E_0 q_0 q(t)=E_0 C+left q_0-E_0 C right left frac k_1 k_1+k_2 t right ^1 / C k_2

Air Resistance In (14) of Section 1.3 we saw that a differential equation describing the velocity v of a falling mass subject to air resistance proportional to the instantaneous velocity is \(m \frac{d v}{d t}=m g-k v\) where k > 0 is a constant of proportionality. The positive direction is downward. (a) Solve the equation subject to the initial condition \(v(0)=v_{0}\). (b) Use the solution in part (a) to determine the limiting, or terminal, velocity of the mass. We saw how to determine the terminal velocity without solving the DE in Problem 40 in Exercises 2.1. (c) If the distance s, measured from the point where the mass was released above ground, is related to velocity v by dsdt v(t), find an explicit expression for s(t) if s(0) = 0. Text Transcription: m \frac{d v}{d t}=m g-k v v(0) = v_0

How High?—Linear Air Resistance Repeat Problem 36, but this time assume that air resistance is proportional to instantaneous velocity. It stands to reason that the maximum height attained by the cannonball must be less than that in part (b) of Problem 36. Show this by supposing that the constant of proportionality is k = 0.0025. [Hint: Slightly modify the DE in Problem 35.]

Skydiving A skydiver weighs 125 pounds, and her parachute and equipment combined weigh another 35 pounds. After exiting from a plane at an altitude of 15,000 feet, she waits 15 seconds and opens her parachute. Assume that the constant of proportionality in the model in Problem 35 has the value k = 0.5 during free fall and k = 10 after the parachute is opened. Assume that her initial velocity on leaving the plane is zero. What is her velocity and how far has she traveled 20 seconds after leaving the plane? See Figure 3.1.13. How does her velocity at 20 seconds compare with her terminal velocity? How long does it take her to reach the ground? [Hint: Think in terms of two distinct IVPs.]

Fluctuating Population The differential equation dP/dt (k = cos t)P, where k is a positive constant, is a mathematical model for a population P(t) that undergoes yearly seasonal fluctuations. Solve the equation subject to \(P(0)=P_{0}\). Use a graphing utility to graph the solution for different choices of \(P_{0}\). Text Transcription: P(0) = P0 P_0

Evaporating Raindrop As a raindrop falls, it evaporates while retaining its spherical shape. If we make the further assumptions that the rate at which the raindrop evaporates is proportional to its surface area and that air resistance is negligible, then a model for the velocity v(t) of the raindrop is \(\frac{d v}{d t}+\frac{3(k / \rho)}{(k / \rho) t+r_{0}} v=g\) Here r is the density of water, \(r_{0}\) is the radius of the raindrop at t = 0, k > 0 is the constant of proportionality, and the downward direction is taken to be the positive direction. (a) Solve for v(t) if the raindrop falls from rest. (b) Reread Problem 36 of Exercises 1.3 and then show that the radius of the raindrop at time t is \(r(t)=(k / \rho) t+r_{0}\). (c) If \(r_{0}=0.01 \mathrm{ft}\) and r = 0.007 ft 10 seconds after the raindrop falls from a cloud, determine the time at which the raindrop has evaporated completely. Text Transcription: Frac d v d t +frac 3(k / rho k / rho) t+r_0 v=g r_0 r(t) = (k/p)t + r_0 r_0 = 0.01 ft

Population Model In one model of the changing population P(t) of a community, it is assumed that \(\frac{d P}{d t}=\frac{d B}{d t}-\frac{d D}{d t}\) where dB/dt and dD/dt are the birth and death rates, respectively. (a) Solve for \(P(t) \text { if } d B / d t=k_{1} P \text { and } d D / d t=k_{2} P\). (b) Analyze the cases \(k_{1}>k_{2}, k_{1}=k_{2}, \text { and } k_{1}<k_{2}\). Text Transcription: fracd P d t= frac d B d t- frac d D d t P(t) if dBdt k1P and dDdt k2P. k_1 > k_2, k_1 = k+2, and k_1 < k_2.

Constant-Harvest Model A model that describes the population of a fishery in which harvesting takes place at a constant rate is given by \(\frac{d P}{d t}=k P-h\) where k and h are positive constants. (a) Solve the DE subject to \(P(0)=P_{0}\). (b) Describe the behavior of the population P(t) for increasing time in the three cases \(P_{0}>h / k, P_{0}=h / k\), and \(0<P_{0}<h / k\). (c) Use the results from part (b) to determine whether the fish population will ever go extinct in finit time, that is, whether there exists a time T > 0 such that P(T) = 0. If the population goes extinct, then find T. Text Transcription: P(0) = P_0. P_0 > h/k, P_0 = h/k 0 < P_0 < h/k

How High?—No Air Resistance Suppose a small cannonball weighing 16 pounds is shot vertically upward, as shown in Figure 3.1.12, with an initial velocity \(v_{0}=300 \mathrm{ft} / \mathrm{s}\). The answer to the question “How high does the cannonball go?” depends on whether we take air resistance into account. (a) Suppose air resistance is ignored. If the positive direction is upward, then a model for the state of the cannonball is given by \(d^{2} s / d t^{2}=-g\) (equation (12) of Section 1.3). Since dsdt v(t) the last differential equation is the same as dv/dt = g, where we take \(g=32 \mathrm{ft} / \mathrm{s}^{2}\). Find the velocity v(t) of the cannonball at time t. (b) Use the result obtained in part (a) to determine the height s(t) of the cannonball measured from ground level. Find the maximum height attained by the cannonball. Text Transcription: v_0 = 300 ft/s d^2 s/d t^2 =-g g = 32 ft/s^2

Drug Dissemination A mathematical model for the rate at which a drug disseminates into the bloodstream is given by \(\frac{d x}{d t}=r-k x\) where r and k are positive constants. The function x(t) describes the concentration of the drug in the bloodstream at time t. (a) Since the DE is autonomous, use the phase portrait concept of Section 2.1 to find the limiting value of \(x(t) \text { as } t \longrightarrow \infty\). (b) Solve the DE subject to x(0) = 0. Sketch the graph of x(t) and verify your prediction in part (a). At what time is the concentration one-half this limiting value? Text Transcription: frac d/x d/t=r-k x x(t) as t longarrow infty

Memorization When forgetfulness is taken into account, the rate of memorization of a subject is given by \(\frac{d A}{d t}=k_{1}(M-A)-k_{2} A\) where \(k_{1}>0, k_{2}>0\), A(t) is the amount memorized in time t, M is the total amount to be memorized, and M A is the amount remaining to be memorized. (a) Since the DE is autonomous, use the phase portrait concept of Section 2.1 to find the limiting value of A(t) as \(t \longrightarrow \infty\). Interpret the result. (b) Solve the DE subject to A(0) 0. Sketch the graph of A(t) and verify your prediction in part (a). Text Transcription: Frac d/A d/t =k_1 M-A -k_2 A k_1 > 0, k_2 > 0 t longrightarrow infty

Sliding Box (a) A box of mass m slides down an inclined plane that makes an angle u with the horizontal as shown in Figure 3.1.15. Find a differential equation for the velocity v(t) of the box at time t in each of the following three cases: (i) No sliding friction and no air resistance (ii) With sliding friction and no air resistance (iii) With sliding friction and air resistance In cases (ii) and (iii), use the fact that the force of friction opposing the motion of the box is \(\mu N\), where \(\mu\) is the coefficient of sliding friction and N is the normal component of the weight of the box. In case (iii) assume that air resistance is proportional to the instantaneous velocity. (b) In part (a), suppose that the box weighs 96 pounds, that the angle of inclination of the plane is \(\theta=30^{\circ}\), that the coefficient of sliding friction is \(=\sqrt{3} / 4\), and that the additional retarding force due to air resistance is numerically equal to \(\frac{1}{4} v\). Solve the differential equation in each of the three cases, assuming that the box starts from rest from the highest point 50 ft above ground. Text Transcription: mu u 30° sqrt{3} / 4 frac{1}{4} v

Sliding Box—Continued (a) In Problem 46 let s(t) be the distance measured down the inclined plane from the highest point. Use ds/dt v(t) and the solution for each of the three cases in part (b) of Problem 46 to find the time that it takes the box to slide completely down the inclined plane. A root finding application of a CAS may be useful here. (b) In the case in which there is friction \((\mu \neq 0)\)but no air resistance, explain why the box will not slide down the plane starting from rest from the highest point above ground when the inclination angle \(\theta\) satisfies tan \(\theta \quad \mu\). (c) The box will slide downward on the plane when tan \(\theta \quad \mu\) if it is given an initial velocity \(v(0)=v_{0}>0\). Suppose that \(=\sqrt{3} / 4\) and \(\theta=23^{\circ}\). Verify that tan \(\theta \quad \mu\). How far will the box slide down the plane if \(v_{0}=1 \mathrm{ft} / \mathrm{s}\)? (d) Using the values and \(=\sqrt{3} / 4 \text { and } \theta=23^{\circ}\), approximate the smallest initial velocity v0 that can be given to the box so that, starting at the highest point 50 ft above ground, it will slide completely down the inclined plane. Then find the corresponding time it takes to slide down the plane. Text Transcription: m neq 0 Theta theta mu v(0) = v_0 > 0 =\sqrt{3} / 4 u = 23^circ v_0 = 1 ft/s =\sqrt{3} / 4 theta=23^{\circ}

Heart Pacemaker A heart pacemaker, shown in Figure 3.1.14, consists of a switch, a battery, a capacitor, and the heart as a resistor. When the switch S is at P, the capacitor charges; when S is at Q, the capacitor discharges, sending an electrical stimulus to the heart. In Problem 53 in Exercises 2.3 we saw that during this time the electrical stimulus is being applied to the heart, the voltage E across the heart satisfies the linear D \(\frac{d E}{d t}=-\frac{1}{R C} E\) (a) Let us assume that over the time interval of length \(t_{1}, 0<t<t_{1}\) the switch S is at position P shown in Figure 3.1.14 and the capacitor is being charged. When the switch is moved to position Q at time \(t_{1}\) the capacitor discharges, sending an impulse to the heart over the time interval of length \(t_{2}: t_{1} \quad t<t_{1}+t_{2}\). Thus over the initial charging/discharging interval \(0<t<t_{1}+t_{2}\) the voltage to the heart is actually modeled by the piecewise-defined differential equation \(\frac{d E}{d t}=\left\{\begin{array}{lll} 0, & 0 & t<t_{1} \\ -\frac{1}{R C} E, & t_{1} & t<t_{1}+t_{2} \end{array}\right.) By moving S between P and Q, the charging and discharging over time intervals of lengths \(t_{1} \text { and } t_{2}\) is repeated indefinitel . Suppose \(t_{1}=4 \mathrm{s}, t_{2}=2 \mathrm{s}\), \(\boldsymbol{E}_{0}=12 \mathrm{V}\), and E(0) 0, E(4) 12, E(6) 0, E(10) 12, E(12) 0, and so on. Solve for E(t) for 0 t 24. (b) Suppose for the sake of illustration that R = C = 1. Use a graphing utility to graph the solution for the IVP in part (a) for 0 t 24. Text Transcription: t_1, 0 < t < t_1 t_1 t_2 t_2: t_1 t < t_1 + t_2 0 < t < t_1+ t_2 frac{d E}{d t}=\left\{\begin{array}{lll} 0, & 0 & t<t_{1} \\ -\frac{1}{R C} E, & t_{1} & t<t_{1}+t_{2} \end{array}\right t_1 = 4 s, t_2 = 2 s E_0 = 12 V