Solution Found!
A mass weighing 16 pounds stretches a spring feet. The
Chapter 5, Problem 29E(choose chapter or problem)
A mass weighing 16 pounds stretches a spring \(\frac{8}{3}\) feet. The mass is initially released from rest from a point 2 feet below the equilibrium position, and the subsequent motion takes place in a medium that offers a damping force that is numerically equal to \(\frac{1}{2}\) the instantaneous velocity. Find the equation of motion if the mass is driven by an external force equal to \(f(t)=10 \cos 3 t\).
Text Transcription:
frac83
frac12
f(t)=10\cos t
Questions & Answers
QUESTION:
A mass weighing 16 pounds stretches a spring \(\frac{8}{3}\) feet. The mass is initially released from rest from a point 2 feet below the equilibrium position, and the subsequent motion takes place in a medium that offers a damping force that is numerically equal to \(\frac{1}{2}\) the instantaneous velocity. Find the equation of motion if the mass is driven by an external force equal to \(f(t)=10 \cos 3 t\).
Text Transcription:
frac83
frac12
f(t)=10\cos t
ANSWER:Step 1 of 6
Converting the given weight to an engineering unit of mass gives us
Following Hooke's Law, we find the spring constant to be
We also have the damping constant as 
