Answer: A cat rides a merry-go-round turning with uniform | StudySoup

Textbook Solutions for Fundamentals of Physics Extended

Chapter 4 Problem 68

Question

A cat rides a merry-go-round turning with uniform circular motion. At time \(t_{1}=2.00 \mathrm{~s}\), the cat’s velocity is \(\vec{v}_{1}=(3.00 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{i}}+(4.00 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{j}}\), measured on a horizontal xy coordinate system. At \(t_{2}=5.00 \mathrm{~s}\), the cat’s velocity is \(\vec{v}_{2}=(-3.00 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{i}}+(-4.00 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{j}}\). What are

(a) the magnitude of the cat’s centripetal acceleration and

(b) the cat’s average acceleration during the time interval \(t_{2}-t_{1}\), which is less than one period?

Solution

Step 1 of 4)

The first step in solving 4 problem number 68 trying to solve the problem we have to refer to the textbook question: A cat rides a merry-go-round turning with uniform circular motion. At time \(t_{1}=2.00 \mathrm{~s}\), the cat’s velocity is \(\vec{v}_{1}=(3.00 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{i}}+(4.00 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{j}}\), measured on a horizontal xy coordinate system. At \(t_{2}=5.00 \mathrm{~s}\), the cat’s velocity is \(\vec{v}_{2}=(-3.00 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{i}}+(-4.00 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{j}}\). What are(a) the magnitude of the cat’s centripetal acceleration and(b) the cat’s average acceleration during the time interval \(t_{2}-t_{1}\), which is less than one period?
From the textbook chapter MOTION IN TWO AND THREE DIMENSIONS you will find a few key concepts needed to solve this.

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Title Fundamentals of Physics Extended 9 
Author David Halliday
ISBN 9780470469088

Answer: A cat rides a merry-go-round turning with uniform

Chapter 4 textbook questions

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