Solution Found!
Reference : Show that the amplitude of the steady-state
Chapter 5, Problem 51E(choose chapter or problem)
QUESTION:
Use Problem 50 to show that the steady-state current in an LRC-series circuit when \(L=\frac{1}{2} \mathrm{~h}, \quad R=20 \Omega\), C = 0.001 f, and E(t) = 100 sin 60t V, is given by \(i_{p}(t)=4.160 \sin (60 t-0.588)\)
Text Transcription:
L=frac12h
R=20Omega
(i_p(t)=4.160sin(60 t-0.588)
Questions & Answers
QUESTION:
Use Problem 50 to show that the steady-state current in an LRC-series circuit when \(L=\frac{1}{2} \mathrm{~h}, \quad R=20 \Omega\), C = 0.001 f, and E(t) = 100 sin 60t V, is given by \(i_{p}(t)=4.160 \sin (60 t-0.588)\)
Text Transcription:
L=frac12h
R=20Omega
(i_p(t)=4.160sin(60 t-0.588)
ANSWER:Step 1 of 3
In this problem we have to prove that the steady state current in given series circuit is given by,