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Chapter 3, Problem 78E(choose chapter or problem)
QUESTION:
If Y has a geometric distribution with success probability .3, what is the largest value, \(y_{0}\), such that \(P\left(Y>y_{0}\right) \geq .1\)?
Questions & Answers
QUESTION:
If Y has a geometric distribution with success probability .3, what is the largest value, \(y_{0}\), such that \(P\left(Y>y_{0}\right) \geq .1\)?
ANSWER:Step 1 of 2
We have random variable ‘Y’ it follows geometric distribution with parameter ‘p = 0.3’.
Then the probability mass function of geometric distribution is given by:
\(P(X)=p(1-p)^{x-1}, x=1,2, \ldots, n\)
Where,
x = random variable
p = probability of success(Parameter)
n = sample size
We need to find the largest value of \(y_{0}\) such that \(\mathrm{P}\left(\mathrm{Y}>y_{0}\right)=0.1\).