A 63.0-mF capacitor is connected to a generator operating at a low frequency. The rms voltage of the generator is 4.00 V and is constant. A fuse in series with the capacitor has negligible resistance and will burn out when the rms current reaches 15.0 A. As the generator frequency is increased, at what frequency will the fuse burn out?
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Question
Part a of the drawing shows a resistor and a charged capacitor wired in series. When the switch is closed, the capacitor discharges as charge moves from one plate to the other. Part b shows the amount q of charge remaining on each plate of the capacitor as a function of time. In part c of the drawing, the switch has been removed and an ac generator has been inserted into the circuit. The circuit elements in the drawing have the following values: R 5 18 V, Vrms 5 24 V for the generator, and f 5 380 Hz for the generator. The time constant for the circuit in part a is t 5 3.0 3 1024 s. What is the rms current in the circuit in part c?
Solution
The first step in solving 23 problem number 24 trying to solve the problem we have to refer to the textbook question: Part a of the drawing shows a resistor and a charged capacitor wired in series. When the switch is closed, the capacitor discharges as charge moves from one plate to the other. Part b shows the amount q of charge remaining on each plate of the capacitor as a function of time. In part c of the drawing, the switch has been removed and an ac generator has been inserted into the circuit. The circuit elements in the drawing have the following values: R 5 18 V, Vrms 5 24 V for the generator, and f 5 380 Hz for the generator. The time constant for the circuit in part a is t 5 3.0 3 1024 s. What is the rms current in the circuit in part c?
From the textbook chapter Alternating Current Circuits you will find a few key concepts needed to solve this.
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