Apply Praseodymium is a lanthanide element that reacts
Chapter , Problem 117(choose chapter or problem)
Apply Praseodymium is a lanthanide element that reacts with hydrochloric acid, forming praseodymium(III) chloride. It also reacts with nitric acid, forming praseodymium(III) nitrate. Praseodymium has the electron configuration [Xe]4 f 3 6 s 2 . a. Examine the electron configuration, and explain how praseodymium forms a 3+ ion. b. Write the correct formulas for both compounds formed by praseodymium.
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