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Consider the following three systems: (i) dx dt = 3 sin x

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QUESTION:

Consider the following three systems: (i) dx dt = 3 sin x + y dy dt = 4x + cos y 1 (ii) dx dt = 3 sin x + y dy dt = 4x + cos y 1 (iii) dx dt = 3 sin x + y dy dt = 4x + 3 cos y 3. All three have an equilibrium point at (0, 0). Which two systems have phase portraits with the same local picture near (0, 0)? Justify your answer. [Hint: Very little computation is required for this exercise, but be sure to give a complete justifi- cation.]

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QUESTION:

Consider the following three systems: (i) dx dt = 3 sin x + y dy dt = 4x + cos y 1 (ii) dx dt = 3 sin x + y dy dt = 4x + cos y 1 (iii) dx dt = 3 sin x + y dy dt = 4x + 3 cos y 3. All three have an equilibrium point at (0, 0). Which two systems have phase portraits with the same local picture near (0, 0)? Justify your answer. [Hint: Very little computation is required for this exercise, but be sure to give a complete justifi- cation.]

ANSWER:

Step 1 of 7

As stated, all three given systems have an equilibrium point at .

For the first system, let:

Then, their partial derivatives are given by:

Substitute 0 for both  and  to obtain their value at  :

Therefore. the Jacobian matrix at. the equilibrium point

=

is given by:

The linearized system

 =

in this case is given by:

=

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