While on a very smooth level transcontinental plane flight, your coffee cup sits motionless on your tray. Are there forces acting on the cup? If so, how do they differ from the forces that would be acting on the cup if it sat on your kitchen table at home?
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Textbook Solutions for Physics for Scientists and Engineers,
Question
A girl holds a stone in her hand and can move it up or down or keep it still. True or false: (a) The force exerted by her hand on the rock is always the same magnitude as the force of gravity on the stone. (b) The force exerted by her hand on the rock is the reaction force to the force of gravity on the stone. (c) The force exerted by her hand on the stone is always the same magnitude as the force on her hand by the stone, but in the opposite direction. (d) If the girl moves her hand down at a constant speed, then her upward force on the stone is less than the force of gravity on the stone. (e) If the girl moves her hand downward but slows the stone to rest, then the force of the stone on the girls hand is the same magnitude as the force of gravity on the stone.
Solution
The first step in solving 4 problem number 20 trying to solve the problem we have to refer to the textbook question: A girl holds a stone in her hand and can move it up or down or keep it still. True or false: (a) The force exerted by her hand on the rock is always the same magnitude as the force of gravity on the stone. (b) The force exerted by her hand on the rock is the reaction force to the force of gravity on the stone. (c) The force exerted by her hand on the stone is always the same magnitude as the force on her hand by the stone, but in the opposite direction. (d) If the girl moves her hand down at a constant speed, then her upward force on the stone is less than the force of gravity on the stone. (e) If the girl moves her hand downward but slows the stone to rest, then the force of the stone on the girls hand is the same magnitude as the force of gravity on the stone.
From the textbook chapter NEWTONS LAWS you will find a few key concepts needed to solve this.
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