Fish contaminated by a plant’s toxic discharge. Refer to

Chapter 3, Problem 83E

(choose chapter or problem)

Get Unlimited Answers
QUESTION:

Problem 83E

Fish contaminated by a plant’s toxic discharge. Refer to the U.S. Army Corps of Engineers’ study on the DDT contamination of fish in the Tennessee River (Alabama), Example 1.5 (p. 13). Part of the investigation focused on how far upstream the contaminated fish have migrated. (A fish is considered to be contaminated if its measured DDT concentration is greater than 5.0 parts per million.)

a. Considering only the contaminated fish captured from the Tennessee River, the data reveal that 52% of the fish are found between 275 and 300 miles upstream, 39% are found 305 to 325 miles upstream, and 9% are found 330 to 350 miles upstream. Use these percentages to determine the probabilities, P(275-300), P(305-325), and P(330-350).

b. Given that a contaminated fish is found a certain distance upstream, the probability that it is a channel catfish (CC) is determined from the data as P(CC|275-300) = .775, P(CC|305-325) = .77, and P(CC|330-350) = .86. If a contaminated channel catfish is captured from the Tennessee River, what is the probability that it was captured 275–300 miles upstream?

Questions & Answers

QUESTION:

Problem 83E

Fish contaminated by a plant’s toxic discharge. Refer to the U.S. Army Corps of Engineers’ study on the DDT contamination of fish in the Tennessee River (Alabama), Example 1.5 (p. 13). Part of the investigation focused on how far upstream the contaminated fish have migrated. (A fish is considered to be contaminated if its measured DDT concentration is greater than 5.0 parts per million.)

a. Considering only the contaminated fish captured from the Tennessee River, the data reveal that 52% of the fish are found between 275 and 300 miles upstream, 39% are found 305 to 325 miles upstream, and 9% are found 330 to 350 miles upstream. Use these percentages to determine the probabilities, P(275-300), P(305-325), and P(330-350).

b. Given that a contaminated fish is found a certain distance upstream, the probability that it is a channel catfish (CC) is determined from the data as P(CC|275-300) = .775, P(CC|305-325) = .77, and P(CC|330-350) = .86. If a contaminated channel catfish is captured from the Tennessee River, what is the probability that it was captured 275–300 miles upstream?

ANSWER:

Solution

Step 1 of 2

a) We have to find the

Given that 52% of the fish found between 275 and 300 miles upstream

Then

Given that 39% of the fish found between 305 and 325 miles upstream

Then

Given that 9% of the fish found between 330 and 350 miles upstream

Then


Add to cart


Study Tools You Might Need

Not The Solution You Need? Search for Your Answer Here:

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back