Figure 14.2a shows the Hope diamond (44.5 carats), which is almost pure carbon. Figure 14.2b shows the Rosser Reeves ruby (138 carats), which is primarily aluminum oxide (Al2O3). One carat is equivalent to a mass of 0.200 g. Determine (a) the number of carbon atoms in the diamond and (b) the number of Al2O3 molecules in the ruby.
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Textbook Solutions for Physics,
Question
Carbon tetrachloride (CCl 4) is diffusing through benzene (C6H6), as the drawing illustrates. The concentration of CCl 4 at the left end of the tube is maintained at 1.00 102 kg/m3 , and the diffusion constant is 20.0 1010 m2 /s. The CCl 4 enters the tube at a mass rate of 5.00 1013 kg/s. Using these data and those shown in the drawing, A find (a) the mass of CCl 4 per second that passes point A and (b) the concentration of CCl 4 at point A.
Solution
The first step in solving 14 problem number 84 trying to solve the problem we have to refer to the textbook question: Carbon tetrachloride (CCl 4) is diffusing through benzene (C6H6), as the drawing illustrates. The concentration of CCl 4 at the left end of the tube is maintained at 1.00 102 kg/m3 , and the diffusion constant is 20.0 1010 m2 /s. The CCl 4 enters the tube at a mass rate of 5.00 1013 kg/s. Using these data and those shown in the drawing, A find (a) the mass of CCl 4 per second that passes point A and (b) the concentration of CCl 4 at point A.
From the textbook chapter The Ideal Gas Law and Kinetic Theory you will find a few key concepts needed to solve this.
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