Find the angular speed of Earth around the Sun in radians per second. (a) 2.22 3 1026 rad/s (b) 1.16 3 1027 rad/s (c) 3.17 3 1028 rad/s (d) 4.52 3 1027 rad/s (e) 1.99 3 1027 rad/s
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Textbook Solutions for College Physics
Question
A merry-go-round rotates with constant angular speed. As a rider moves from the rim of the merry-go-round toward the center, what happens to the magnitude of total centripetal force that must be exerted on him? (a) It increases. (b) It is not zero, but remains the same. (c) It decreases. (d) Its always zero. (e) It increases or decreases, depending on the direction of rotation.
Solution
The first step in solving 7 problem number trying to solve the problem we have to refer to the textbook question: A merry-go-round rotates with constant angular speed. As a rider moves from the rim of the merry-go-round toward the center, what happens to the magnitude of total centripetal force that must be exerted on him? (a) It increases. (b) It is not zero, but remains the same. (c) It decreases. (d) Its always zero. (e) It increases or decreases, depending on the direction of rotation.
From the textbook chapter Multiple Choice Questions you will find a few key concepts needed to solve this.
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