Convert 3.50 3 103 cal to an equivalent number of joules. (a) 2.74 3 104 J (b) 1.47 3 104 J (c) 3.24 3 104 J (d) 5.33 3 104 J (e) 7.20 3 105 J
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Textbook Solutions for College Physics
Question
A student measures the following data in a calorimetry experiment designed to determine the specific heat of aluminum: Initial temperature of water and calorimeter: 70.0C Mass of water: 0.400 kg Mass of calorimeter: 0.040 kg Specific heat of calorimeter: 0.63 kJ/kg ? C Initial temperature of aluminum: 27.0C Mass of aluminum: 0.200 kg Final temperature of mixture: 66.3C Use these data to determine the specific heat of aluminum. Explain whether your result is within 15% of the value listed in Table 11.1.
Solution
The first step in solving 11 problem number trying to solve the problem we have to refer to the textbook question: A student measures the following data in a calorimetry experiment designed to determine the specific heat of aluminum: Initial temperature of water and calorimeter: 70.0C Mass of water: 0.400 kg Mass of calorimeter: 0.040 kg Specific heat of calorimeter: 0.63 kJ/kg ? C Initial temperature of aluminum: 27.0C Mass of aluminum: 0.200 kg Final temperature of mixture: 66.3C Use these data to determine the specific heat of aluminum. Explain whether your result is within 15% of the value listed in Table 11.1.
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