Problem 41P

As a train accelerates away from a station, it reaches a speed of 4.7 m/s in 5.0 s. If the train's acceleration remains constant, what is its speed after an additional 6.0 s has elapsed?

Solution 41P

Step 1 of 1

We have to the speed of a train after an additional 6.0 s has elapsed, as it accelerated away from a station and reached a speed of 4.7 m/s in 5.0 s

The speed of the train after an elapse of additional 6.0 s can be found using the equation

Where,

s

m/s

acceleration after 5.0 s in m/s2

Now, the acceleration after 5.0 s can be found using the equation

Where,

initial velocity = 0 m/s

4.7 m/s

5 s

Thus,

=

= 0.94 m/s2

Hence, the speed of the train after an elapse of additional 6.0 s is

= 10.34 m/s

Therefore, the speed of the train after an elapse of additional 6.0 s is 10.34 m/s.