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Physics / Physics with MasteringPhysics 4 / Chapter 10 / Problem 106GP

Physics with MasteringPhysics | 4th Edition | ISBN: 9780321541635 | Authors: James S. Walker

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The pulsar in the Crab nebula ( 9) was created by a

Chapter 10, Problem 106GP

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QUESTION:

Problem 106GP

The pulsar in the Crab nebula (Problem 9) was created by a supernova explosion that was observed on Earth in A.D. 1.054. Its current period of rotation (33.0 ms) is observed to be increasing by 1.26 × 10−5 seconds per year. (a) What is the angular acceleration of the pulsar in rad/s2? (b) Assuming the angular acceleration of the pulsar to be constant, how many years will it take for the pulsar to slow to a stop? (c) Under the same assumption, what was the period of the pulsar when it was created?

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QUESTION:

Problem 106GP

The pulsar in the Crab nebula (Problem 9) was created by a supernova explosion that was observed on Earth in A.D. 1.054. Its current period of rotation (33.0 ms) is observed to be increasing by 1.26 × 10−5 seconds per year. (a) What is the angular acceleration of the pulsar in rad/s2? (b) Assuming the angular acceleration of the pulsar to be constant, how many years will it take for the pulsar to slow to a stop? (c) Under the same assumption, what was the period of the pulsar when it was created?

ANSWER:

a.)

Step 1 of 4

We have to find the angular acceleration of the pulsar whose current period of rotation (33.0 ms) is observed to be increasing by 1.26 $\times{}1{0}^{5}$ seconds per year.

The angular acceleration of the pulsar over the 1 $-$ year time interval can be found using the expression,

Where,

$\Delta{}\omega{}$ = change in angular speed over the time

interval of 1 year.

$\Delta{}t=$ time interval of 1 year = 3.16 $\times{}1{0}^{7}$ s

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