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When you arrive at Duke's Dude Ranch, you are greeted by

Chapter 11, Problem 100GP

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QUESTION:

When you arrive at Duke’s Dude Ranch, you are greeted by the large wooden sign shown in Figure 11–42. The left end of the sign is held in place by a bolt, the right end is tied to a rope that makes an angle of \(20^\circ\) with the horizontal. If the sign is uniform, 3.20 m long, and has a mass of 16.0 kg, what are (a) the tension in the rope, and (b) the horizontal and vertical components of the force, F, exerted by the bolt?

Equation Transcription:

Text Transcription:

20.0^o

vec{F}

vec{F}

20.0^o

m vec{g}

vec{T}

L=1.60 m

L=1.60 m

Questions & Answers

QUESTION:

When you arrive at Duke’s Dude Ranch, you are greeted by the large wooden sign shown in Figure 11–42. The left end of the sign is held in place by a bolt, the right end is tied to a rope that makes an angle of \(20^\circ\) with the horizontal. If the sign is uniform, 3.20 m long, and has a mass of 16.0 kg, what are (a) the tension in the rope, and (b) the horizontal and vertical components of the force, F, exerted by the bolt?

Equation Transcription:

Text Transcription:

20.0^o

vec{F}

vec{F}

20.0^o

m vec{g}

vec{T}

L=1.60 m

L=1.60 m

ANSWER:

Solution 100GP

Part (a)

Step 1az:

A large wooden board is tied to a rope at an angle θ at one end and the other end of the board is fixed to a bolt. The length and the mass of the board are given. We are going to find the tension in the rope. The center of mass of the board is assumed to be at the exact center of the board.

The length of the board 2L = 3.20 m

The mass of the board m = 16.0 kg

The acceleration due to gravity g = 9.81 m/s2

The angle above the horizontal θ = 20.0°

The location of the center of mass L = 1.60 m

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