Answer: A hollow aluminum cylinder 20.0 cm deep has an

Problem 21 

A hollow aluminium cylinder 20.0 cm deep has an internal capacity of 2.000 L at  It is completely filled with turpentine at . The turpentine and the aluminium cylinder are then slowly warmed together to . (a) How much turpentine overflows? (b) What is the volume of turpentine remaining in the cylinder at ? (c) If the combination with this amount of turpentine is then cooled back to , how far below the cylinders rim does the turpentines surface recede?

Step by step solution

Step 1 of 3

The volume of cylinder and turpentine is .

The depth of the aluminium cylinder is

The initial temperature of the cylinder and turpentine is .

The final temperature of the cylinder and turpentine is .

In order to calculate part (a), (b), and (c), we need to estimate the expansion coefficients of cylinder and turpentine.

Refer to the table of coefficient of expansion of different material, the standard value of coefficient of thermal expansion of aluminium cylinder is  and the value of coefficient of thermal expansion of turpentine is .

(A)

The overflow volume of turpentine when temperature is increased to 80 oC is,

Here, Vturpentine is the increased volume of the turpentine and Vcylinder is the increased volume of the cylinder.

For , , ,  and .

Therefore,

The overflow volume of turpentine when temperature is increased to 80 oC is .