In a certain region of space, the electric field is zero. From this fact, what can you conclude about the electric potential in this region? (a) It is zero. (b) It does not vary with position. (c) It is positive. (d) It is negative. (e) None of those answers is necessarily true.
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Textbook Solutions for Physics for Scientists and Engineers with Modern Physics
Question
A GeigerMueller tube is a radiation detector that consists of a closed, hollow, metal cylinder (the cathode) of inner radius ra and a coaxial cylindrical wire (the anode) of radius rb (Fig. P25.68a). The charge per unit length on the anode is l, and the charge per unit length on the cathode is 2l. A gas fills the space between the electrodes. When the tube is in use (Fig. P25.68b) and a high-energy elementary particle passes through this space, it can ionize an atom of the gas. The strong electric field makes the resulting ion and electron accelerate in opposite directions. They strike other molecules of the gas to ionize them, producing an avalanche of electrical discharge. The pulse of electric current between the wire and the cylinder is counted by an external circuit. (a) Show that the magnitude of the electric potential difference between the wire and the cylinder is DV 5 2ke l ln a ra rb b (b) Show that the magnitude of the electric field in the space between cathode and anode is E 5 DV ln 1ra/rb 2 a 1 r b where r is the distance from the axis of the anode to the point where the field is to be calculated.
Solution
The first step in solving 25 problem number 68 trying to solve the problem we have to refer to the textbook question: A GeigerMueller tube is a radiation detector that consists of a closed, hollow, metal cylinder (the cathode) of inner radius ra and a coaxial cylindrical wire (the anode) of radius rb (Fig. P25.68a). The charge per unit length on the anode is l, and the charge per unit length on the cathode is 2l. A gas fills the space between the electrodes. When the tube is in use (Fig. P25.68b) and a high-energy elementary particle passes through this space, it can ionize an atom of the gas. The strong electric field makes the resulting ion and electron accelerate in opposite directions. They strike other molecules of the gas to ionize them, producing an avalanche of electrical discharge. The pulse of electric current between the wire and the cylinder is counted by an external circuit. (a) Show that the magnitude of the electric potential difference between the wire and the cylinder is DV 5 2ke l ln a ra rb b (b) Show that the magnitude of the electric field in the space between cathode and anode is E 5 DV ln 1ra/rb 2 a 1 r b where r is the distance from the axis of the anode to the point where the field is to be calculated.
From the textbook chapter Electric Potential you will find a few key concepts needed to solve this.
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