A solenoid with 385 turns per meter and a diameter of 17.0 cm has a magnetic flux through its core of magnitude 1.28 × 10−4 T · m2. (a) Find the current in this solenoid, (b) How would your answer to part (a) change if the diameter of the solenoid were doubled? Explain.
Step 1 of 3
Here we have to calculate the current through the solenoid and the change in the magnetic field if the diameter is doubled.
The equation for the magnitude of magnetic flux is,
Where - Intensity of magnetic field
- Area of cross section of the surface
- Angle between the area vector and the magnetic field vector
The equation for the magnetic field of a solenoid.
Where, - Permeability of free space
- Number of turns per metre
- Current through the circuit
Textbook: Physics with MasteringPhysics
Author: James S. Walker
Physics with MasteringPhysics was written by and is associated to the ISBN: 9780321541635. Since the solution to 7P from 23 chapter was answered, more than 531 students have viewed the full step-by-step answer. This full solution covers the following key subjects: solenoid, diameter, flux, current, Answer. This expansive textbook survival guide covers 32 chapters, and 3833 solutions. This textbook survival guide was created for the textbook: Physics with MasteringPhysics, edition: 4. The full step-by-step solution to problem: 7P from chapter: 23 was answered by , our top Physics solution expert on 07/27/17, 10:59AM. The answer to “A solenoid with 385 turns per meter and a diameter of 17.0 cm has a magnetic flux through its core of magnitude 1.28 × 10?4 T · m2. (a) Find the current in this solenoid, (b) How would your answer to part (a) change if the diameter of the solenoid were doubled? Explain.” is broken down into a number of easy to follow steps, and 53 words.