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IP A hydrogen atom has an orbital angular momentrum with a
Chapter 31, Problem 43P(choose chapter or problem)
IP A hydrogen atom has an orbital angular momentum with a magnitude of \(10 \sqrt{57}(h / 2 \pi)\)
(a) Determine the value of the quantum number \(\ell\) for this atom.
(b) What is the minimum possible value of this atom's principal quantum number, Explain.
(c) If \(10 \sqrt{57}(h / 2 \pi)\) is the maximum orbital angular momentum this atom can have, what is its energy?
Equation Transcription:
ℓ
Text Transcription:
10 \sqrt{57}(h / 2 \pi)
\ell
10 \sqrt{57}(h / 2 \pi)
Questions & Answers
QUESTION:
IP A hydrogen atom has an orbital angular momentum with a magnitude of \(10 \sqrt{57}(h / 2 \pi)\)
(a) Determine the value of the quantum number \(\ell\) for this atom.
(b) What is the minimum possible value of this atom's principal quantum number, Explain.
(c) If \(10 \sqrt{57}(h / 2 \pi)\) is the maximum orbital angular momentum this atom can have, what is its energy?
Equation Transcription:
ℓ
Text Transcription:
10 \sqrt{57}(h / 2 \pi)
\ell
10 \sqrt{57}(h / 2 \pi)
ANSWER:Step 1 of 4
Here, we have to calculate the orbital quantum number, principal quantum number and the energy.
The equation for the orbital angular momentum.
The equation for the energy.
a)