The center of the pulley is being lifted vertically with an acceleration of 4 m>s2 at | StudySoup

Textbook Solutions for Engineering Mechanics Dynamics (1) 1

Chapter 16 Problem R16-5

Question

The center of the pulley is being lifted vertically with an acceleration of \(4 \ m/s^{2}\) at the instant it has a velocity of 2 m/s. If the cable does not slip on the pulley’s surface, determine the accelerations of the cylinder B and point C on the pulley

Solution

Step 1 of 2

Given: \(\vec{a}=4\hat{j}\mathrm{\ m}/\mathrm{s}^2\),  \(\vec{v}=2\hat{j}\mathrm{m}/\mathrm{s}\), \(r=0.08\mathrm{\ m}\)

Angular acceleration and velocity are equal to:

\(\begin{array}{l} \alpha=\frac{a}{r}=\frac{4}{0.08}=50 \mathrm{rad} / \mathrm{s}^{2} \\ \omega=\frac{v}{r}=\frac{2}{0.08}=25 \mathrm{rad} / \mathrm{s} \end{array}\)

And both of them are in \(-\hat{k}\) direction

Displacement of point C relative to the point A is \(\vec{r}_{C/A}=-0.08\hat{i}\ m\)

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full solution

Title Engineering Mechanics Dynamics (1) 1 14 
Author Russell C. Hibbeler
ISBN 9780133915389

The center of the pulley is being lifted vertically with an acceleration of 4 m>s2 at

Chapter 16 textbook questions

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