A satellite orbiting the moon very near the surface has a period of 110 min. Use this information, together with the radius of the moon from the table on the inside of the back cover, to calculate the free-fall acceleration on the moon’s surface.
Solution Step 1 of 2 Time period of the satellite is the time required to perform one complete revolution in the orbit. Here for the satellite orbiting the moon near the surface time period is given by is given by, T = 2 r g Where T is the time period, r is the radius of the orbit and g is the freely falling acceleration on moon surface. Solving for freely falling acceleration, g = 4 2 2 T