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A satellite orbiting the moon very near the surface has a

Calculus: Early Transcendentals | 1st Edition | ISBN: 9780321570567 | Authors: William L. Briggs, Lyle Cochran, Bernard Gillett ISBN: 9780321570567 2

Solution for problem 27P Chapter 6

Calculus: Early Transcendentals | 1st Edition

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Calculus: Early Transcendentals | 1st Edition | ISBN: 9780321570567 | Authors: William L. Briggs, Lyle Cochran, Bernard Gillett

Calculus: Early Transcendentals | 1st Edition

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Problem 27P

A satellite orbiting the moon very near the surface has a period of 110 min. Use this information, together with the radius of the moon from the table on the inside of the back cover, to calculate the free-fall acceleration on the moon’s surface.

Step-by-Step Solution:

Solution Step 1 of 2 Time period of the satellite is the time required to perform one complete revolution in the orbit. Here for the satellite orbiting the moon near the surface time period is given by is given by, T = 2 r g Where T is the time period, r is the radius of the orbit and g is the freely falling acceleration on moon surface. Solving for freely falling acceleration, g = 4 2 2 T

Step 2 of 2

Chapter 6, Problem 27P is Solved
Textbook: Calculus: Early Transcendentals
Edition: 1
Author: William L. Briggs, Lyle Cochran, Bernard Gillett
ISBN: 9780321570567

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