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For the closed tank with Bourdon-tube gages tapped into it, what is the specific gravity

Chapter 3, Problem 3.16

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QUESTION:

For the closed tank with Bourdon-tube gages tapped into it, what is the specific gravity of the oil and the pressure reading on gage C?

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QUESTION:

For the closed tank with Bourdon-tube gages tapped into it, what is the specific gravity of the oil and the pressure reading on gage C?

ANSWER:

Step 1 of 3

The pressure acting at point B is given by,

\(\mathrm{P}_{\mathrm{B}}=\mathrm{P}_{\mathrm{A}}+\mathrm{h}_{\mathrm{o}} \gamma_{\mathrm{o}}\)

Where \(P_{A}\) is the pressure at point A, \(\gamma_{0}\) is the specific weight of the oil, and \(h_{o}\) is the height of the oil level.

Substituting the known values,

\(\begin{aligned}
58.53 \times 10^{3} & =50 \times 10^{3}+\mathrm{Y}_{0} \times 1 \\
\gamma_{\circ} & =8530 \mathrm{~N} / \mathrm{m}^{3}
\end{aligned}\)

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