In the circuit of Fig. 10.71, is1 = 8 cos (4t 9) mA, is2 = 5 cos 4t and vs3 = 2 sin 4t

Chapter 10, Problem 67

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In the circuit of Fig. 10.71, \(i_{s1} = 8\ cos\ (4t - 9^{\circ})\ mA\), \(i_{s2} = 5\ cos\ 4t\) and \(v_{s3} = 2\ sin\ 4t\). (a) Redraw the circuit in the phasor domain; (b) reduce the circuit to a single current source with the assistance of a source transformation; (c) calculate \(v_L(t)\). (d) Verify your solution with an appropriate PSpice simulation.

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