Solution Found!
Solved: For what value of b is continuous at every x?
Chapter 2, Problem 46E(choose chapter or problem)
QUESTION:
For what value of \(b\) is
\(g(x)= \begin{cases}\frac{x-b}{b+1}, & x<0 \\ x^{2}+b, & x>0\end{cases}\)
continuous at every \(x\)?
Equation Transcription:
{
Text Transcription:
b
g(x)={_x^2+b, x>0 x-b/b+1,x<0
x
Questions & Answers
QUESTION:
For what value of \(b\) is
\(g(x)= \begin{cases}\frac{x-b}{b+1}, & x<0 \\ x^{2}+b, & x>0\end{cases}\)
continuous at every \(x\)?
Equation Transcription:
{
Text Transcription:
b
g(x)={_x^2+b, x>0 x-b/b+1,x<0
x
ANSWER:
Solution
Step 1 of 3
In this problem, we have to find value of for which the given function is continuous at every
Given that
,
And ,
.