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Ch 9 - 65P
Chapter 9, Problem 65P(choose chapter or problem)
The carbon isotope \({ }^{14} \mathrm{C}\) is used for carbon dating of archeological artifacts. \({ }^{14} \mathrm{C}\) (mass \(2.34 \times 10^{-26} \mathrm{~kg}\) ) decays by the process known as beta decay in which the nucleus emits an electron (the beta particle) and a subatomic particle called a neutrino. In one such decay, the electron and the neutrino are emitted at right angles to each other. The electron (mass \(9.11 \times 10^{-31} \mathrm{~kg}\) ) has a speed of \(5.0 \times 10^{7} \mathrm{~m} / \mathrm{s}\) and the neutrino has a momentum of \(8.0 \times 10^{-24} \mathrm{~kg} \mathrm{~m} / \mathrm{s}\). What is the recoil speed of the nucleus?
Equation Transcription:
Text Transcription:
^14 C
^14 C
2.34 X 10^{-26} kg
9.11 X 10^{-31} kg
5.0 X 10^{7} m/s
8.0 X 10^{-24} kg m/s
Questions & Answers
QUESTION:
The carbon isotope \({ }^{14} \mathrm{C}\) is used for carbon dating of archeological artifacts. \({ }^{14} \mathrm{C}\) (mass \(2.34 \times 10^{-26} \mathrm{~kg}\) ) decays by the process known as beta decay in which the nucleus emits an electron (the beta particle) and a subatomic particle called a neutrino. In one such decay, the electron and the neutrino are emitted at right angles to each other. The electron (mass \(9.11 \times 10^{-31} \mathrm{~kg}\) ) has a speed of \(5.0 \times 10^{7} \mathrm{~m} / \mathrm{s}\) and the neutrino has a momentum of \(8.0 \times 10^{-24} \mathrm{~kg} \mathrm{~m} / \mathrm{s}\). What is the recoil speed of the nucleus?
Equation Transcription:
Text Transcription:
^14 C
^14 C
2.34 X 10^{-26} kg
9.11 X 10^{-31} kg
5.0 X 10^{7} m/s
8.0 X 10^{-24} kg m/s
ANSWER:Step 1 of 2
We are required to calculate the recoil speed of the nucleus.