Solved: Evaluate the dot product if

Chapter 11, Problem 2E

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QUESTION:

Evaluate the dot product \(\vec{A} \cdot \vec{B}\) if

a. \(\vec{A}=4 \hat{\imath}-2 \hat{\jmath}\) and \(\vec{B}=-2 \hat{\imath}-3 \hat{\jmath}\)

b. \(\vec{A}=-4 \hat{\imath}+2 \hat{\jmath}\) and \(\vec{B}=2 \hat{\imath}+4 \hat{\jmath}\)

Equation Transcription:

Text Transcription:

vec A cdot vec B

vec A = 4 \hat i - 2 \hat j

vec B = -2 \hat i - 3 \hat j

vec A = -4 \hat i + 2 \hat j

vec B = 2 \hat i + 4 \hat j

Questions & Answers

QUESTION:

Evaluate the dot product \(\vec{A} \cdot \vec{B}\) if

a. \(\vec{A}=4 \hat{\imath}-2 \hat{\jmath}\) and \(\vec{B}=-2 \hat{\imath}-3 \hat{\jmath}\)

b. \(\vec{A}=-4 \hat{\imath}+2 \hat{\jmath}\) and \(\vec{B}=2 \hat{\imath}+4 \hat{\jmath}\)

Equation Transcription:

Text Transcription:

vec A cdot vec B

vec A = 4 \hat i - 2 \hat j

vec B = -2 \hat i - 3 \hat j

vec A = -4 \hat i + 2 \hat j

vec B = 2 \hat i + 4 \hat j

ANSWER:

Step 1 of 2

a)

Here we have to find the dot product of the two vectors.

\(\vec{A}=4 \hat{i}-2 \hat{j}\)

\(\vec{B}=-2 \hat{i}-3 \hat{j}\)

We know that,

\(\vec{A} \cdot \vec{B}=A_{x} B_{x}+A_{y} B_{y}\)

\(=4 \times(-2)+(-2) \times(-3)\)

\(=-8+6=-2\)

 

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