Problem 59P

0.10 mol of gas undergoes the process 1 → 2 shown in FIGURE.

a. What are temperatures T 1 and T 2 (in °C)?

b. What type of process is this?

c. The gas undergoes an isothermal compression from point 2 until the volume is restored to the value it had at point 1. What is the final pressure of the gas?

FIGURE

Solution 59 P

a.)

Step 1 of 3

We have to find the temperatures and of 0.1 mol of a gas which undergoes the process shown in the given figure.

The gas undergoes an isobaric process (constant pressure pressure) as the initial and final pressure (atm) are the same which can be seen from the figure.

The temperatures and of the gas can be found using the ideal gas equation.

Where,

atm = 101300 Pa

cm3 = 1000m3(from figure)

J/mol K

Thus,

Where,

atm = 101300 Pa

cm3 = 3000m3(from figure)

J/mol K

Thus,

Therefore, the temperatures and are 152 oC and 93o C respectively.

b.)