Menthol (?= 156.3 g/mol). a strong-smelling substance used

Chapter 3, Problem 34P

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QUESTION:

Menthol (\(\mathscr{M}\) = 156.3 g/mol), a strong-smelling substance used in cough drops, is a compound of carbon, hydrogen, and oxygen. When 0.1595 g of menthol was subjected to combustion analysis, it produced 0.449 g of \(\mathrm{CO}_{2}\), and 0.184 g of \(\mathrm{H}_{2} \mathrm{O}\). What is menthol's molecular formula?

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QUESTION:

Menthol (\(\mathscr{M}\) = 156.3 g/mol), a strong-smelling substance used in cough drops, is a compound of carbon, hydrogen, and oxygen. When 0.1595 g of menthol was subjected to combustion analysis, it produced 0.449 g of \(\mathrm{CO}_{2}\), and 0.184 g of \(\mathrm{H}_{2} \mathrm{O}\). What is menthol's molecular formula?

ANSWER:

Step 1 of 4

Here, we have to calculate the molecular formula of Menthol.

 

First, let’s find the molar mass of individual elements in Menthol.

\(\text { Mass of Carbon }=\text { Mass of } \mathrm{CO}_{2} \times \frac{1 \text { mol of } \mathrm{C} \times \text { Molar mass of } \mathrm{C}}{\text { Mass of } 1 \text { mol of CO }}\)

We know,

Mass of \(\mathrm{CO}_{2}\) = 0.449g

Molar mass of C = 12.01 g

Mass of 1 mol of \(\mathrm{CO}_{2}\) = 44.01g

\(\frac{0.449 \times 12.01}{44.01}=0.122 \mathrm{~g}\).

Therefore, mass of carbon is 0.122g.

\(\text{ Mass of Hydrogen }=\text{ Mass of }\mathrm{H}_2\mathrm{O}\times\frac{1\text{ mol of }\mathrm{H}\times\text{ Molar mass of }\mathrm{H}}{\text{ Mass of }1\text{ mol of }H_2\mathrm{O}}\)

 

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