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Menthol (?= 156.3 g/mol). a strong-smelling substance used
Chapter 3, Problem 34P(choose chapter or problem)
Menthol (\(\mathscr{M}\) = 156.3 g/mol), a strong-smelling substance used in cough drops, is a compound of carbon, hydrogen, and oxygen. When 0.1595 g of menthol was subjected to combustion analysis, it produced 0.449 g of \(\mathrm{CO}_{2}\), and 0.184 g of \(\mathrm{H}_{2} \mathrm{O}\). What is menthol's molecular formula?
Questions & Answers
QUESTION:
Menthol (\(\mathscr{M}\) = 156.3 g/mol), a strong-smelling substance used in cough drops, is a compound of carbon, hydrogen, and oxygen. When 0.1595 g of menthol was subjected to combustion analysis, it produced 0.449 g of \(\mathrm{CO}_{2}\), and 0.184 g of \(\mathrm{H}_{2} \mathrm{O}\). What is menthol's molecular formula?
ANSWER:
Step 1 of 4
Here, we have to calculate the molecular formula of Menthol.
First, let’s find the molar mass of individual elements in Menthol.
\(\text { Mass of Carbon }=\text { Mass of } \mathrm{CO}_{2} \times \frac{1 \text { mol of } \mathrm{C} \times \text { Molar mass of } \mathrm{C}}{\text { Mass of } 1 \text { mol of CO }}\)
We know,
Mass of \(\mathrm{CO}_{2}\) = 0.449g
Molar mass of C = 12.01 g
Mass of 1 mol of \(\mathrm{CO}_{2}\) = 44.01g
\(\frac{0.449 \times 12.01}{44.01}=0.122 \mathrm{~g}\).
Therefore, mass of carbon is 0.122g.
\(\text{ Mass of Hydrogen }=\text{ Mass of }\mathrm{H}_2\mathrm{O}\times\frac{1\text{ mol of }\mathrm{H}\times\text{ Molar mass of }\mathrm{H}}{\text{ Mass of }1\text{ mol of }H_2\mathrm{O}}\)