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If 25.0 mL of silver nitrate solution reacts with excess
Chapter 4, Problem 29P(choose chapter or problem)
QUESTION: If 25.0 mL of silver nitrate solution reacts with excess potassium chloride solution to yield 0.842 g of precipitate, what is the molarity of silver ion in the original solution?
Questions & Answers
QUESTION: If 25.0 mL of silver nitrate solution reacts with excess potassium chloride solution to yield 0.842 g of precipitate, what is the molarity of silver ion in the original solution?
ANSWER:
Step 1 of 3
Here, we are going to determine the molarity of silver ions in the original solution.
Molarity is defined as follows:
\(\text { Molarity }=\frac{\text { Moles of solute }}{\text { Volume of solution in L }}\)
The balanced equation is
\(\mathrm{AgNO}_{3}(a q)+\mathrm{KCl}(a q) \rightarrow \mathrm{KNO}_{3}(a q)+\mathrm{AgCl}(s)\)