How many moles of gaseous arsine (AsH3) occupy 0.0400 L at

Solution 33P

Here, we have to calculate the moles and density of gaseous arsine (AsH3) occupy 0.0400 L at STP.

Step 1 of 2

a.

Let’s write the formula to calculate the number of moles of arsine.

PV = nRT

Rearrange the formula is as follows.

n = 

At STP 

P = 1 atm

T = 273K

R= 0.0821 atm.L.mol-1.K-1.

Given, V = 0.0400 L.

Let’s calculate the number of moles of arsine.

n = 

  = 1.78 x 10-3  mol

Therefore, number of moles of arsine is 1.78 x 10-3 mol.

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