A mixture of CO2 and Kr weighs 35.0 g and exerts a

Solution 95P:

Step 1:

Here, we are going to calculate the mass of CO2(g) originally present in the mixture.

Given that

Total mass of the mixture =35.0 g

Let us consider, the mass of CO2(g) and Kr are x and y respectively

Thus,

Total pressure =0.708 atm

Let us consider P1 and P2 are the partial pressures of Kr and CO2 respectively.

Since,

From the ideal gas equation

For Kr gas,

----(3)

For CO2 (g)

----(4)

Therefore, putting the values of (3) and (4) in (2) we get

(----(5)

Now, we know that

Moles of gas =

Thus (5) implies

(

) =0.708 ---(6)