Solution Found!
Write the full electron configuration of the Period 2
Chapter 8, Problem 44P(choose chapter or problem)
Write the full electron configuration of the Period 2 element with the following successive IEs (in kJ/mol):
IE1 = 801
IE2 = 2427
IE3 = 3659
IE4 = 25,022
IE5 = 32,822
Questions & Answers
QUESTION: Problem 44P
Write the full electron configuration of the Period 2 element with the following successive IEs (in kJ/mol):
IE1 = 801
IE2 = 2427
IE3 = 3659
IE4 = 25,022
IE5 = 32,822
ANSWER:
Solution 44P:
Here, we are going to write the full electron configuration of the Period 2 element with the following successive IEs (in kJ/mol).
Step 1: Ionization Energy (IE): It the amount of energy required when 1.0 mol of electron is removed to 1.0 mol of atom to form the gaseous ion.
For example: Atom +e- ion++ e-
Successive ionization energies increases slowly from one valence electron to the next, but the ionization energy increases suddenly for the first core electron.
The second ionization energy (IE2) removes a second electron from the positively charged ion. Therefore, IE2 is always larger than IE1.
ion+ion2+ (g) + e-
(IE2 > IE1)