Solved: Show that the Dirichlet function is not continuous at any real number
Chapter 1, Problem 110(choose chapter or problem)
Show that the Dirichlet function
\(f(x)=\left\{\begin{array}{ll} 0, & \text { if } x \text { is rational } \\ 1, & \text { if } x \text { is irrational } \end{array}\right.\)
is not continuous at any real number.
Text Transcription:
f(x) = {_1, if x is irrational ^0, if x is rational
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